Answer:
The angular momentum of the system is 0.18kgm²/s
Explanation:
L = angular momentum of the particle 1 + angular momentum of the particle 2
L = ml²ω + ml²ω
L = 2ml²ω
Given that,
m = 500g are connected by a massless cord
=0.500kg
l = 30cm
= 0.30m
angular speed ω = 2.0 rev/s
angular momentum of the system =
L = 2ml²ω
L = 2 × 0.500 × (0.30)² × 2
L = 2 × 0.500 × 0.09 × 2
L = 0.18kgm²/s
Thus, the angular momentum of the system is 0.18kgm²/s
