contestada

If you combine 250.0 mL 250.0 mL of water at 25.00 ∘ C 25.00 ∘C and 100.0 mL 100.0 mL of water at 95.00 ∘ C, 95.00 ∘C, what is the final temperature of the mixture? Use 1.00 g/mL as the density of water.

Respuesta :

Answer:

The final temperature of the mixture is = 45 °c

Explanation:

Given data

[tex]V_{1}[/tex] = 250 ml

[tex]T_{1}[/tex] = 25 °c

[tex]V_{2}[/tex] = 100 ml

[tex]T_{2}[/tex] = 95 °c

[tex]V_{1} T_{1} +V_{2} T_{2} = V_{3} T_{3}[/tex]

Put all the values in above formula we get

250 × 25 + 100 × 95 = [tex]V_{3} T_{3}[/tex]

[tex]V_{3} T_{3}[/tex] = 15750 ------ (1)

[tex]V_{3} = V_{1} + V_{2}[/tex]

[tex]V_{3} =[/tex] 250 + 100 = 350 ml

Put this value in equation (1) we get

[tex]T_{3} = \frac{15750}{350}[/tex]

[tex]T_{3}[/tex] = 45 °c

Therefore the final temperature of the mixture is = 45 °c

Otras preguntas