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A car of mass 980.0 kg accelerates away from an intersection on a horizontal road. When the car speed is 37.4 km/hr (10.4 m/s), the net power which the engine supplies is 5500.0 W (in addition to the extra power required to make up for air resistance and friction). Calculate the acceleration of the car at that time.

Respuesta :

Answer:

Acceleration will be equal to [tex]acceleration=0.5396m/sec^2[/tex]

Explanation:

We have given mass of the car m = 980 kg

Velocity of the car v = 37.4 km/hr = 10.4 m/sec

Power supplied by the engine P = 5500 watt

We know that power is rate of change of energy with respect to time

So [tex]Power=\frac{energy}{time}[/tex]

Energy is equal to energy = force × distance

So [tex]Power=\frac{force\times distance}{time}[/tex]

From newtons second law force is equal to Force = mass × acceleration

So [tex]Power=mass\times acceleration\times \frac{distance}{time}[/tex]

[tex]Power=mass\times acceleration\times velocity[/tex]

So [tex]5500=980\times acceleration\times 10.4[/tex]

[tex]acceleration=0.5396m/sec^2[/tex]

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