Answer:
18.5 degree Celsius
Explanation:
We are given that
Partial pressure of gas=[tex]P_1[/tex]=72.92 KPa
Total pressure gas =P=75.02 KPa
We have to find the temperature at which the gas was collected.
We know that
Total pressure,P=[tex]P_1+P_2[/tex]
[tex]P_2=P-P_1=75.02-72.92=2.1 KPa[/tex]
Water vapor pressure=[tex]P_2=2.1 KPa[/tex]
[tex]P_2=\frac{2.1\times 760}{101.3}mm Hg=15.76mm Hg[/tex]
101.3 KPa=760 mm Hg
Temperature when water vapor pressure is 15.75 mm Hg=18.5 degree Celsius
The temperature at which gas collected=18.5 degree Celsius
