Respuesta :
Step-by-step explanation:
You missed to add the graph. I possibly found and attached the complete graph question below.
From the attached graph,
Given the portion of piecewise function
[tex]f(x) = -2[/tex]
has the domain [tex]-10<x<0[/tex].
In other words, the graph of this portion is showing discontinuty or hole occurs at x = 0 and x = -10. Therefore, It does not include x = 0 and x = -10.
- A discontinuity occurs when a gap or hole appears in the graph.
Similarly, the portion of piecewise function
[tex]y = 2x+1[/tex]
has the domain [tex]0<x<4[/tex].
As the graph of this portion is showing discontinuty or hole occurs at x = 0 and x = -4. Therefore, the domain does not include x = 0 and x = -4.
And the 3rd the portion of piecewise function
[tex]f\left(x\right)=-\frac{1}{2}x[/tex]
has the domain [tex]4<x<8[/tex].
As the graph of this portion is showing discontinuty or hole occurs at x = 4 and x = 8. Therefore, the domain does not include x = 4 and x = 8.
