Respuesta :

Step-by-step explanation:

You missed to add the graph. I possibly found and attached the complete graph question below.

From the attached graph,

Given the portion of piecewise function

[tex]f(x) = -2[/tex]

has the domain [tex]-10<x<0[/tex].

In other words, the graph of this portion is showing discontinuty or hole occurs at x = 0 and x = -10. Therefore, It does not include x = 0 and x = -10.

  • A discontinuity occurs when a gap or hole appears in the graph.

Similarly, the portion of piecewise function

[tex]y = 2x+1[/tex]

has the domain [tex]0<x<4[/tex].

As the graph of this portion is showing discontinuty or hole occurs at x = 0 and x = -4. Therefore, the domain does not include x = 0 and x = -4.

And the 3rd the portion of piecewise function

[tex]f\left(x\right)=-\frac{1}{2}x[/tex]

has the domain [tex]4<x<8[/tex].

As the graph of this portion is showing discontinuty or hole occurs at x = 4 and x = 8. Therefore, the domain does not include x = 4 and x = 8.

Ver imagen SaniShahbaz

Dude its

-10<x<0

0<x<4

4<x<8