Answer:
3.12 km
320.19°
Explanation:
From the diagram, the starting point is O.
The resultant is line OC.
Hence, using Pythagoras Theorem, we have that:
OC² = OE² + EC²
OC² = 2.4² + 2²
OC² = 5.76 + 4
OC² = 9.76
OC = 3.12 km
The angle, θ, will be:
tanθ = (2/2.4)
tanθ = 0.833
θ = 39.81°
Measuring counterclockwise from the East, the angle will be 360 - 39.81 = 320.19°.
Answer:
a) the distance is 3.12 km
b) Angle is 244.35 degrees
Explanation:
As per attached diagram, we construct a triangle OAB where:
OB = 2.4 km
AB = 2.0 km
OA = ??
Using Pythagoras theorem on triangle OAB to find OA:
[tex](OA)^{2} = (OB)^2 + (AB)^2\\(OA)^{2} = 2.4^2 + 2.0^2\\OA = 3.12 km[/tex]
The final angle will be equal to 180 (east to west) added to the angle AOB
[tex]Angle AOB = Tan^-^1 (\frac{5}{2.4})[/tex]
Angle AOB = 64.35 degrees
Adding AOB with the angle between east and west i.e. 180 degrees
Angle = 180 + Angle AOB
Angle = 244.35 degrees
