Answer:
The number of loops in first coil is 64
Explanation:
Given :
Induced emf in first coil [tex]\epsilon _{1} =[/tex] 1.23 V
Induced emf in second coil [tex]\epsilon _{2} =[/tex] 4.56 V
No. loops in second coil [tex]N_{2} = 234[/tex]
We have to find no. loops in first coil
Apply faraday's law to each coil,
[tex]\epsilon =- N\frac{d\phi}{dt}[/tex]
Now compare above equation,
[tex]\frac{\epsilon _{1} }{N_{1} } = \frac{\epsilon _{2} }{N_{2} }[/tex]
So loops in first coil is,
[tex]N_{1} = \frac{\epsilon _{1} N_{2} }{\epsilon _{2} }[/tex]
[tex]N_{1} = \frac{234 \times 1.23}{4.56}[/tex]
[tex]N_{1} = 63.11[/tex] ≅ 64
Therefore, the number of loops in first coil is 64
