Answer: The required fraction would be
[tex]\dfrac{6}{12},\dfrac{7}{12},..............etc[/tex]
Step-by-step explanation:
Since we have given that
Length of first piece = [tex]\dfrac{5}{12}\ feet[/tex]
She needs the second piece longer than the first,
So, the length of second piece would be
[tex]x>\dfrac{5}{12}[/tex]
So, it can be
[tex]\dfrac{6}{12},\dfrac{7}{12},\dfrac{8}{12},.........[/tex]
Hence, the required fraction would be
[tex]\dfrac{6}{12},\dfrac{7}{12},..............etc[/tex]