On July 1 of last year, the total number of employees at Company E was decreased by 10 percent. Without any change in the salaries of the remaining employees, the average (arithmetic mean) employee salary was 10 percent more after the decrease in number of employees than before the decrease. The total of the combined salaries of all of the employees at Company E after July 1 last year was what percent of that before July 1 last year?

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chachi4201 chachi4201 · Answer 1 · 2020-04-02T17:37:47+02:00

Answer:

The total of the combined salaries of all of the employees at Company E after July 1 last year was 99 percent of that before July 1 last year

Step-by-step explanation:

Before July 1

Let the total no of employee is n

Let the average salary of employee is x

After July 1

The total no of employee is decreased by 10%

Then the no of employee is = [tex]n-n\times\frac{10}{100}[/tex]

= [tex]\frac{9n}{10}[/tex]

Average salary of employee is increased by 10%

then the average salary of employee is = [tex]x + x\times\frac{10}{100}[/tex]

= [tex]\frac{11x}{10}[/tex]

Before July 1

The total salary of employee is =

After July 1

The total salary of employee nx is = [tex]\frac{9n}{10}\times\frac{11x}{10}[/tex]

Let the total of the combined salaries of all of the employees at Company E after July 1 last year was p percent of that before July 1 last year =

[tex](n)(x)\times \frac{t}{100} = \frac{9n}{10}\times\frac{11x}{10}[/tex]

t = 99