Answer:
Step-by-step explanation:
ok i have this same question so what you are going to take the 3 and just maove it to the side and then you fail
472.97 pounds of 3% milk and 27.03 pounds 40% cream would be needed to make 500 pounds of 5% milk
Given :
3% milk and 40% cream would be needed to make 500 pounds of 5% milk
Let x be the number of pounds of milk
y be the number of pound of cream
Total pounds is 500
[tex]x+y=500\\x=(500-y)\\[/tex]
Now we frame the second equation using percentage
To remove percentage we divide by 100
3% milk and 40% cream would be needed to make 500 pounds of 5% milk
[tex]0.03x+0.4y=500(0.05)\\[/tex]
Replace x in the second equation
[tex]0.03\left(500-y\right)+0.4y=500\cdot \:0.05\\15-0.03y+0.4y=25\\15+0.37y=25\\0.37y=10\\y=\frac{10}{0.37} =27.03[/tex]
Now we find out x
[tex]x=500-y\\x=500-27.03\\x=472.97[/tex]
So, 472.97 pounds of 3% milk and 27.03 pounds 40% cream would be needed to make 500 pounds of 5% milk
Learn more : brainly.com/question/4053986
