Respuesta :
Answer: The mass of potassium sulfate that can be produced is 73.88 grams
Explanation:
To calculate the number of moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex] .....(1)
- For KOH:
Given mass of KOH = 23.8 g
Molar mass of KOH = 56.1 g/mol
Putting values in equation 1, we get:
[tex]\text{Moles of KOH}=\frac{23.8g}{56.1g/mol}=0.424mol[/tex]
The chemical equation for the reaction of KOH and potassium hydrogen sulfate follows:
[tex]KHSO_4+KOH\rightarrow K_2SO_4+H_2O[/tex]
As, potassium hydrogen sulfate is present in excess. It is considered as an excess reagent.
KOH is considered as a limiting reagent because it limits the formation of product.
By Stoichiometry of the reaction:
1 mole of KOH produces 1 mole of potassium sulfate
So, 0.424 moles of KOH will produce = [tex]\frac{1}{1}\times 0.424=0.424moles[/tex] of potassium sulfate
Now, calculating the mass of potassium sulfate from equation 1, we get:
Molar mass of potassium sulfate = 174.26 g/mol
Moles of potassium sulfate = 0.424 moles
Putting values in equation 1, we get:
[tex]0.424mol=\frac{\text{Mass of potassium sulfate}}{174.26g/mol}\\\\\text{Mass of potassium sulfate}=(0.424mol\times 174.26g/mol)=73.88g[/tex]
Hence, the mass of potassium sulfate that can be produced is 73.88 grams
