Respuesta :
Answer:
B=4*10^{-6} T
Explanation:
you can take this wire as two independent wires joint as the point (0,0)
the magnitude of the magnetic field is the contribution of both parts
B1+B2=B
[tex]B=\frac{\mu_0I}{2\pi r}[/tex]
I: current
mu_0: magnetic permeability
r: distance to the wire
Then, we have
[tex]B=2\frac{(4\pi*10^{-7}\frac{Tm}{A})(2.0A)}{2\pi (0.2m)}\\B=4*10^{-6}T[/tex]
Hope this helps!!
Answer:
The value is = 4 x 10∧-6T
Explanation:
Let us assume or take the wire as two independent wires joint as the point (0,0)
The magnetic field (magnitude) is both parts of the contribution.
Which is,
B1+B2 =B
B = µ₀I/πr
Where,
I=The current in the wire
µ₀= The magnetic permeability
r= distance to the wire
Therefore,
B= 2 (4π x 10-7 Tm/A) (2.0A)/2π (0.2m) or
B= 2 (4π x 10-7 Tm/A) (2.0A)/2π (0.2m) (0.2m)
The value is = 4 x 10-∧6 T