A line that is parallel to another line has the same slope, but different y-intercept. Since we already know the slope and have a point for this problem, we can use the generic slope intercept form and plug in our point to find the y-intercept for this new line.
y = 5x + b
-1 = 5(2) + b
-1 = 10 + b
-11 = b
Our final equation is y = 5x - 11.
Hope this helps!! :)
