Answer: The molar concentration of [tex]OH^-[/tex] in the solution is 0.2 M
Explanation:
Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.
[tex]Molarity=\frac{n\times 1000}{V_s}[/tex]
where,
n= moles of solute =[tex]\frac{\text {given mass}}{\text {molar mass}}=\frac{1.77g}{171g/mol}=0.010[/tex]
[tex]V_s[/tex] = volume of solution in ml = 100 ml
[tex]Molarity=\frac{0.010\times 1000}{100}=0.1M[/tex]
[tex]Ba(OH)_2\rightarrow Ba^{2+}+2OH^-[/tex]
As 1 mole of [tex]Ba(OH)_2[/tex] gives 2 moles of [tex]OH^-[/tex]
Thus 0.1 moles of [tex]Ba(OH)_2[/tex] gives = [tex]\frac{2}{1}\times 0.1=0.2[/tex] moles of [tex]OH^-[/tex]
The molar concentration of [tex]OH^-[/tex] in the solution is 0.2 M
