Respuesta :
Answer : The volume of [tex]SO_2[/tex] gas is, [tex]2.75\times 10^6mL[/tex]
Explanation : Given,
Mass of S = 4.10 kg = 4100 g (1 kg = 1000 g)
Molar mass of S = 32 g/mol
First we have to calculate the moles of S.
[tex]\text{Moles of }S=\frac{\text{Given mass }S}{\text{Molar mass }S}=\frac{4100g}{32g/mol}=128.125mol[/tex]
Now we have to calculate the moles of [tex]SO_2[/tex]
The balanced chemical reaction is:
[tex]S(s)+O_2(g)\rightarrow SO_2(g)[/tex]
From the balanced reaction, we conclude that
As, 1 mole of [tex]S[/tex] react to give 1 mole of [tex]SO_2[/tex]
So, 128.125 mole of [tex]S[/tex] react to give 128.125 mole of [tex]SO_2[/tex]
Now we have to calculate the volume of [tex]SO_2[/tex] by using ideal gas equation.
[tex]PV=nRT[/tex]
where,
P = Pressure of [tex]SO_2[/tex] gas = 1.16 atm
V = Volume of [tex]SO_2[/tex] gas = ?
n = number of moles [tex]SO_2[/tex] = 128.125 mole
R = Gas constant = [tex]0.0821L.atm/mol.K[/tex]
T = Temperature of [tex]SO_2[/tex] gas = [tex]30^oC=273+30=303K[/tex]
Putting values in above equation, we get:
[tex]1.16atm\times V=128.125mole\times (0.0821L.atm/mol.K)\times 303K[/tex]
[tex]V=2747.65L=2.75\times 10^6mL[/tex] (1 L = 1000 mL)
Therefore, the volume of [tex]SO_2[/tex] gas is, [tex]2.75\times 10^6mL[/tex]
The volume of SO2 gas (in mL) formed at 30°C and 1.16 atm should be 2.75*10^6 mL.
Calculation of the volume:
Since
Mass of S = 4.10 kg = 4100 g (1 kg = 1000 g)
Molar mass of S = 32 g/mol
Here first determine the mole of S
So,
= 4100 / 32
= 128.125 mol
Now the volume should be
We know that
PV = nRT
Here
P = Pressure of gas = 1.16 atm
n = number of moles = 128.125 mole
R = Gas constant = 0.0821 L
T = Temperature of gas = 30 degrees = 273 + 30 = 303 k
So,
1.16atm * v = 128.125 * (0.0821) * 303
= 2747.65 L
= 2.75*10^6 mL
Learn more about volume here: https://brainly.com/question/14423944
