Answer:
[tex]8.9 m/s^2[/tex]
Explanation:
The period of a simple pendulum is given by the equation
[tex]T=2\pi \sqrt{\frac{L}{g}}[/tex]
where
L is the lenght of the pendulum
g is the acceleration due to gravity at the location of the pendulum
We notice from the formula that the period of a pendulum does not depend on the mass of the system
In this problem:
-The pendulum comes back to the point of release exactly 2.4 seconds after the release. --> this means that the period of the pendulum is
T = 2.4 s
- The length of the pendulum is
L = 1.3 m
Re-arranging the equation for g, we can find the acceleration due to gravity on the planet:
[tex]g=(\frac{2\pi}{T})^2 L=(\frac{2\pi}{2.4})^2(1.3)=8.9 m/s^2[/tex]
