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Orange light of wavelength 0.61 µ m in air enters a block of glass with εr = 1.44. What color would it appear to a sensor embedded in the glass? The wavelength ranges of colors are violet (0.39 to 0.45 µ m), blue (0.45 to 0.49 µ m), green (0.49 to 0.58 µ m), yellow (0.58 to 0.60 µ m), orange (0.60 to 0.62 µ m), and red (0.62 to 0.78 µ m)

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Answer:

[tex]0.5083\ \mu m[/tex]

Explanation:

[tex]\lambda_0[/tex] = Actual wavelength = [tex]0.61\ \mu m[/tex]

[tex]\varepsilon_r[/tex] = Relative permittivity = 1.44

The observed wavelength in the glass is given by

[tex]\lambda=\dfrac{\lambda_0}{\sqrt{\varepsilon_r}}\\\Rightarrow \lambda=\dfrac{0.61}{\sqrt{1.44}}\\\Rightarrow \lambda=0.5083\ \mu m[/tex]

The wavelength lies in the range of green light.

Hence, the observed color of light is [tex]0.5083\ \mu m[/tex]

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