Answer:
Magnification will be equal to 3
Explanation:
We have given focal length of the converging lens [tex]F_1=20cm[/tex]
Focal length of the diverging lens [tex]F_2=30cm[/tex]
Object is placed 40 cm to the length of the converging lens d = 40 cm
Combination of the focal length will be equal to
[tex]\frac{1}{F}=\frac{1}{F_1}+\frac{1}{F_2}[/tex]
[tex]\frac{1}{F}=\frac{1}{20}+\frac{1}{-30}=\frac{1}{20}-\frac{1}{30}=\frac{1}{60}[/tex]
F = 60 cm
So combination of the focal length will be 60 cm
Magnification is given by
[tex]M=\frac{F}{F-d}=\frac{60}{60-40}=3[/tex]
So magnification will be equal to 3
