Answer:
Magnetic field, B = 17.2 T
Explanation:
Given that,
The maximum current in a superconducting solenoid can be as large as 3.75 kA.
The number of turns per meter in such a solenoid is 3650, n = 3650
The magnetic field produced due to solenoid is given by :
[tex]B=\mu_o nI\\\\B=4\pi \times 10^{-7}\times 3650\times 3.75\times 10^3\\\\B=17.2\ T[/tex]
So, the magnitude of the magnetic field it produces is 17.2 T.
