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You throw a ball with a mass of 0.50 kg against a brick wall. It hits the wall moving horizontally to the left at 20 m/s and rebounds horizontally to the right at 10 m/s. (a) Find the impulse of the net force on the ball during its collision with wall. (b) If the ball is in contact with the wall for 1.0 ms (0.001 s), find the magnitude of average horizontal force that the wall exerts on the ball during the impact.

Respuesta :

Answer:

The value of impulse of the net force on the ball during its collision with wall is  [tex]I = 15\ kg \frac{m}{s}[/tex]

The value of average horizontal force that the wall exerts on the ball during the impact is F = 15000 N

Explanation:

Mass of the ball = 0.5 kg

Horizontal velocity [tex]V_{x}[/tex] = 20 [tex]\frac{m}{s}[/tex]

Velocity after collision [tex]V_{-x}[/tex] = - 10 [tex]\frac{m}{s}[/tex]

(A). Impulse of the net force on the ball during its collision with wall is

[tex]I = m (V_{x} - V_{-x})[/tex]

I = 0.5 × (20 + 10)

[tex]I = 15\ kg \frac{m}{s}[/tex]

This is the value of impulse of the net force on the ball during its collision with wall.

(B). The magnitude of average horizontal force

[tex]F = \frac{I}{T}[/tex]

Where F = Force

I = impulse & t = time interval = 0.001 sec

[tex]F = \frac{15}{0.001}[/tex]

F = 15000 N

This is the value of average horizontal force that the wall exerts on the ball during the impact.

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