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An assault rifle fires an eight-shot burst in 0.40 s. Each bullet has a mass of 7.5 g and a speed of 300 m/s as it leaves the gun. What is the average recoil force on the gun during that 0.40 s burst?

Respuesta :

Answer:

The average recoil force on the gun during that 0.40 s burst is 45 N.

Explanation:

Mass of each bullet, m = 7.5 g = 0.0075 kg

Speed of the bullet, v = 300 m/s

Time, t = 0.4 s

The change in momentum of an object is equal to impulse delivered. So,

[tex]F\times t=mv\\\\F=\dfrac{mv}{t}[/tex]

For 8 shot burst, average recoil force on the gun is :

[tex]F=\dfrac{8mv}{t}\\\\F=\dfrac{7.5}{1000}\cdot\dfrac{300}{0.4}\cdot8\\\\F=45\ N[/tex]

So, the average recoil force on the gun during that 0.40 s burst is 45 N.

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