Answer:
The amount of ammonia needed is 33.3 g
Therefore, we can also say 1.96 moles of NH₃
Explanation:
The reaction is: 3CuO(s) + 2NH₃(g) → 3H₂O(l) + 3Cu(s) + N₂(g)
If we see stoichiometry, 3 moles of water can be produced by 2 moles of NH₃. We propose this rule of three:
3 moles of water can be produced by 2 mole of ammonia
Then, 2.94 moles of water, must be produced by (2.94 . 2) /3 =1.96 moles of NH₃
If we convert the moles to mass. 1.96 mol . 17 g /1mol = 33.3 g
