Respuesta :
Answer:
0.43 grams is the maximum mass of sodium sulfate that could be produced by the chemical reaction.
Explanation:
Mass of sulfuric acid = 0.98 g
Moles of sulfuric acid = [tex]\frac{0.98 g}{98 g/mol}=0.010 mol[/tex]
Mass of sodium hydroxide = 0.240 g
Moles of sodium hydroxide = [tex]\frac{0.240 g}{40 g/mol}=0.0060 mol[/tex]
[tex]H_2SO_4(aq)+2NaOH(s)\rightarrow Na_2SO_4(aq)+2H_2O(l)[/tex]
According to reaction, 2 moles of sodium hydroxide reacts with 1 mole of sulfuric acid , then 0.0060 moles of sodium hydroxide will react with :
[tex]\frac{1}{2}\times 0.0060 mol=0.0030 mol[/tex] of sulfuric acid
As we can see that we have 0.010 moles of sulfuric acid but only 0.0030 moles of sulfuric acid will react which indicates that it is in excessive amount where as sodium hydroxide is in limiting amount.
So, amount of sodium sulfate to be formed will depend upon moles of sodium hydroxide.
According to reaction, 2 moles of sodium hydroxide gives with 1 mole of sodium sulfate , then 0.0060 moles of sodium hydroxide will give :
[tex]\frac{1}{2}\times 0.0060 mol=0.0030 mol[/tex] of sodium sulfate
Mass of 0.0030 moles of sodium sulfate :
0.0030 mol × 142 g/mol = 0.426 g ≈ 0.43 g
0.43 grams is the maximum mass of sodium sulfate that could be produced by the chemical reaction.
