Respuesta :
Answer:
The mass ratio for chlorine is = 2 : 1
Explanation:
Given that Compound A contains 8.43 g of chlorine for every 13.67 g of oxygen.
[tex]Compound \ A = \frac{8.43 \ gm \ cl_{2} }{13.67 \ gm \ o_{2} }[/tex]
[tex]Compound \ A = \frac{0.6167 \ gm \ cl_{2} }{1 \ gm \ o_{2} }[/tex] -------- (1)
Similarly
[tex]Compound \ B = \frac{5.87 \ gm \ cl_{2} }{17.33 \ gm \ o_{2} }[/tex] --------- (2)
[tex]Compound \ B = \frac{0.338 \ gm \ cl_{2} }{1 \ gm \ o_{2} }[/tex]
[tex]Mass \ Ratio = \frac{Compound \ A}{Compound \ B}[/tex] ------ (3)
Put the values from equation (1) & (2) in equation (3) we get
[tex]Mass Ratio \ M = \frac{0.6167}{0.338}[/tex]
Mass Ratio = 2 : 1
Therefore the mass ratio for chlorine is = 2 : 1
