Answer:
Common ratio r = 2
Step-by-step explanation:
[tex] \because [/tex] the fith term of a G.P is 8 times the 2nd term.
[tex]\therefore \: t_5 = 8\times t_2 \\ \therefore \: ar^{5-1}=8\times \: ar^{2-1} \\ \therefore \: r^{4}=8\times \: r^{1} \\ \therefore \: r^{3}=8 \\ \therefore \:r^{3}= {2}^{3} \\ \hspace{20 pt}\huge \red{ \boxed{\therefore \:r= {2}}} \\ [/tex]
Hence, common ratio is 2.
Answer:
The common ratio is 2
Step-by-step explanation:
T_n = ar^(n-1)
T_5 = 8(T_2)
r = ?
T_5 = ar^4
T_2 = ar
Therefore
ar^4 = 8ar
Divide both sides by ar, we have
r³ = 8
Taking the cube root of both sides, the result is
r = 2
The common ratio is 2
