Answer:
13 and 12
QUADRATIC EQUATION
Step-by-step explanation:
let the numbers be x and x+1
such that x(x+1)=156
x²+x=156
x²+x-156=0 factorizing the qaudratic equation we have;
(x+13)(x-12)=0
x= -13 and 12
Answer:
The numbers are 12 and 13 and -13 and -12. It's a quadratic equation.
Step-by-step explanation:
Integers are "whole" numbers, they don't have decimals, so if two integers are consecutive they can be related by a sum of 1, if one integer can be called "x" and the next one can be called "y" then y = x + 1. In this case the product of the two must be 156 so we have:
x * y = 156
We can apply the equation that relates the two integers in order to obtain only one variable, such as:
x *( x + 1) = 156
x^2 + x = 156
x^2 + x - 156 = 0
We have two possible values for x:
x1 = (-1 + sqrt(1^2 - 4*1*(-156)))/(2*1)
x1 = (-1 + sqrt(1 + 624))/2 = (-1 + sqrt(625))/2
x1 = (-1 + 25)/2 = 24/2 = 12
x2 = (-1 - 25)/2 = -26/2 = -13
For x1 we have:
y = x + 1 = 12 + 1 = 13
And for x2 we have:
y = -13 + 1 = -12
The numbers are 12 and 13 and -13 and -12.
