Answer:
0.075 T
Explanation:
When a current-carrying wire is immersed in a region with magnetic field, the wire experiences a force, given by
[tex]F=ILB sin \theta[/tex]
where
I is the current in the wire
L is the length of the wire
B is the strength of the magnetic field
[tex]\theta[/tex] is the angle between the direction of I and B
In this problem we have:
L = 0.65 m is the length of the wire
I = 8.2 A is the current in the wire
F = 0.40 N is the force experienced by the wire
[tex]\theta=90^{\circ}[/tex] since the current is at right angle with the magnetic field
Solving the formula for B, we find the strength of the magnetic field:
[tex]B=\frac{F}{IL sin \theta}=\frac{0.40}{(8.2)(0.65)(sin 90^{\circ})}=0.075 T[/tex]
