Answer:
see below
Step-by-step explanation:
Pythagorean theorem:
[tex]a^2 + b^2 = c^2 \\a = \sqrt{c^2-b^2} \\b = \sqrt{c^2-a^2} \\c = \sqrt{a^2+b^2}[/tex], where c is hypotenuse, a and b are the other 2 sides in triangle
1. [tex]x = \sqrt{9^2-3^2}[/tex] = [tex]\sqrt{81-9} = \sqrt{72} = \sqrt{36*2} = 6\sqrt{2}[/tex]
2. [tex]x = \sqrt{18^2-10^2} =\sqrt{324-100} = \sqrt{224} =\sqrt{16*14} =4\sqrt{14}[/tex]
3. [tex]x = \sqrt{4^2+14^2} =\sqrt{16+196} =\sqrt{212} =\sqrt{4*53} =2\sqrt{53}[/tex]
