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akindelemf

Answer:

The pOH of a 0.0010 M solution of calcium hydroxide (Ca(OH)2) is 2.699

Explanation:

Ca(OH)2 = Ca2+ + 2OH-

Molarity of Ca(OH)2 = 2 x molarity of OH-

Molarity of OH- = 2 x 0.0010

                          = 2 x 10^-3

pOH = -log OH-

        = - log ( 2 x 10^-3)

       = 2.699

Answer:

2.699

Explanation:

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