kenediiiii
contestada

1. A 20m steel wire is stretched to 20.0m by

the application of a force of 50N. What force

should be applied to stretch the wire to become

20.05m within its elastic limits?

A. 50 N

B. 100 N

C. 250 N

D. 40,000 N​

Respuesta :

Answer:

Force to stretch the wire is 250 N

Explanation:

As we know that modulus of elasticity will remain the same for the wire if the applied stretch to the wire is within elastic limit

So we will have

[tex]\frac{F L}{\Delta L A} = constant[/tex]

now we have

[tex]\frac{F_1 L}{\Delta L_1 A} = \frac{F_2 L}{\Delta L_2 A}[/tex]

so we can write it as

[tex]F_2 = \frac{F_1 L_2}{L_1}[/tex]

[tex]F_2 = \frac{50 (0.05)}{0.01}[/tex]

[tex]F_2 = 250 N[/tex]

Otras preguntas