Answer:
∠CAB = 20°
Step-by-step explanation:
Looking at the diagram, we can see that ADC is a straight line so it is a 180°. Using this information, we can find the ∠CDE :
∠CDE = 180° - ∠ADE
= 180° - 130°
= 50°
Triangle CDE is an isosceles triangle so ∠CDE = ∠CED = 50° and now, we can find the angle of C :
∠C = 180° - ∠CDE - ∠CED (angle in a triangle is 180°)
= 180° - 50° - 50°
= 80°
Given that triangle ABC is also an isosceles triangle so ∠C = ∠B = 80° and lastly, we can find ∠CAB :
∠CAB = 180° - ∠C - ∠B
= 180° - 80° - 80°
= 20°
