Respuesta :

alarsen0901

Answer:

9 ways

Step-by-step explanation:

Let's begin by listing all possible options. Let a equal the number of pins knocked down on the first try and b equal the number of pins knocked down on the second try.

  1. a = 9, b = 1
  2. a = 8, b = 2
  3. a = 7, b = 3
  4. a = 6, b = 4
  5. a = 5, b = 5
  6. a = 4, b = 6
  7. a = 3, b = 7
  8. a = 2, b = 8
  9. a = 1, b = 9

Assuming that a and b cannot equal 0 (that is, 0 pins knocked down on one try and 10 knocked down on the other), there are 9 possible combinations.

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