Answer:
The cannons total flight time is 2.23seconds
Explanation:
A ball fired diagonally is fired at an angle of 45° to the horizontal. The motion of the fired ball is a projectile motion. A projectile is a motion in which an object fired into space with an initial velocity U is allowed to fall freely under the influence of gravitational force.
To total time of flight T of the cannon ball can be expressed as;
T = 2Usin(theta)/g where;
U is the initial velocity or speed of the ball = 31m/s
theta is the angle that the ball make with the horizontal = 45°
g is the acceleration due to gravity = 9.81m/s²
Substituting the given datas into the formula we have;
T = 31sin45°/9.81
T = 31×0.7071/9.81
T = 21.92/9.81
T = 2.23seconds
The total flight time of the cannon ball is 4.62 s
ime of Flight: This is the total time taken for a projectile to return to the same level at which it was projected.
The formular of time of flight is
T = 2usin∅/g.................... Equation 1
Where, T = Time of flight, u = initial velocity, ∅ = angle of projection, g = acceleration due to gravity.
From the question,
Given: u = 32 m/s, ∅ = 45° (diagonally)
Constant: g = 9.8 m/s²
Substitute these values into equation 1
T = 2(32)(sin45°)/9.8
T = 64*0.7071/9.8
T = 4.62 s
Hence, the Time of flight is 4.62 s
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