Answer:
Given points ( -10 , -3) and (5, -9)
Step-by-step explanation:
First calculating slope ( m)
= ( y2 - y1) / ( x2 - x1)
= -3+9/ -10-5
= 6/-15
= - 2/5
The equation of line is given by
y - y1 = m ( x - x1)
y +9 = -2/5 ( x -5)
5 (y + 9) = -2 (x -5 )
5y + 45 = -2x + 10
2x + 5y +45 -10 =0
2x + 5y +35 = 0
Which is the required equation
Answer:
y = 1.6x -17
Step-by-step explanation:
Point Slope Form: y-y₁=m(x-x₁)
1. We will use this format to Find the equation of a line through the points (-10,-3) (5,-9)
2. Calculate the slope from 2 points
m = y2 - y1 / x2- x1
m = -9 - (-3) / 5- (-10)
m = -6/ 15
m = 1.6
3. Substitute the slope for 'm' in the slope intercept form of the equation
y = mx +b
y = 1.6x +b
4. Substitute either point into the equation. You can use either (-10,-3) or (5,-9)
y = 1.6x +b
-9 = 1.6(5) + b
5. Solve for b, which is the y-intercept of the line
-9 = 1.6(5) + b
-9 = 8 + b
-9 = 8 + b
-17 = b
6. Substitute b, -17, into the equation from step 3
y = 1.6x +b
y = 1.6x -17
