Answer:y=-4
Step-by-step explanation:
To find this
We get,
The difference between the square of the number
Let y be the unknown number
Square of y=y^2
Y^2-28=3y
Then let we are going to rearrange, then we get
y^2-3y-28
We are going to factorise
y^2-7y+4y-28
(y^2-7y+(4y-28)
y(y-7)+4(y-7)=0
(y+4)(y-7)=0
To find the negative number then we have
y=-4
