The probability for each of the following events shown below,
- P(blue) [tex]=\frac{8}{26}=\frac{4}{13}[/tex]
- P(brown) [tex]=\frac{7}{26}[/tex]
- P(green or yellow) = [tex]\frac{11}{26}[/tex]
- P(not blue or brown) =[tex]\frac{11}{26}[/tex]
- P(green, yellow, blue, or brown) =[tex]\frac{26}{26}=1[/tex]
- P(yellow) =[tex]\frac{6}{26} =\frac{3}{13}[/tex]
Probability :
It is given that, there are 5 green, 6 yellow, 8 blue, and 7 brown object.
Total number of object [tex]=5+6+8+7=26[/tex]
Number of blue = 8
Number of brown = 7
Number of green and yellow = 5 + 6 = 11
Number of object that are not blue or brown = 11
Number of object that are green, yellow, blue and brown = 26
Number of yellow object = 6
Now, we have to find probability,
P(blue) [tex]=\frac{8}{26}=\frac{4}{13}[/tex]
P(brown) [tex]=\frac{7}{26}[/tex]
P(green or yellow) = [tex]\frac{11}{26}[/tex]
P(not blue or brown) =[tex]\frac{11}{26}[/tex]
P(green, yellow, blue, or brown) =[tex]\frac{26}{26}=1[/tex]
P(yellow) =[tex]\frac{6}{26} =\frac{3}{13}[/tex]
Learn more about the probability here:
https://brainly.com/question/25870256
