Answer:
0.035 mole
Explanation:
To solve this problem, let us calculate the molar mass of NaOH. This is illustrated below:
Molar Mass of NaOH = 23 + 16 + 1 = 40g/mol
Mass of NaOH from the question = 1.4g
Number of mole of NaOH =?
Number of mole = Mass /Molar Mass
Number of mole of NaOH = 1.4/40
Number of mole of NaOH = 0.035 mole.
Therefore, 0.035 mole of NaOH is present in 1.4g of NaOH.
