Answer:
0.29 M
Explanation:
We are given;
- The number of moles of Lithium sulfate as 734 mol
- The mass of of Lithium sulfate solution as 2500 kg
We are needed to determine the molarity of lithium sulfate solution.
We need to know that;
Molarity of a solution = Moles of the solute ÷ Volume of the solution
Taking the density of the solution to be 1 000 kg/m³ or 1 g/cm³
Then;
Volume = Mass ÷ density
= 2500 kg ÷ 1000 kg/m³
= 2.5 m³
But, 1 m³ = 1000 L
Thus, volume = 2500 L
Therefore;
Molarity = 734 mol ÷ 2500 L
= 0.2936 mol/L
= 0.29 M
Therefore, the molarity of lithium sulfate solution is 0.29 M
