Answer:
The systems of equations are [tex]\left \{ {{r\geq 1; \ \ d+2\leq r} \atop {4r+2d\leq 40}} \right.[/tex] .
Step-by-step explanation:
Given:
Cost of each rose = $4
Cost of each daises = $2
[tex]'r'[/tex] represents the number of roses he buys.
[tex]'d'[/tex] represents the number of daisies he buys.
We need to write the system of equations.
Solution:
Now given:
He wants at least one rose.
so we can say that;
[tex]r\geq 1[/tex]
Also Given:
He wants at least two more daisies then roses.
so we can say that;
[tex]d+2\leq r[/tex]
Now we can say that;
Cost of each rose multiplied by number of roses he buys plus Cost of each daises multiplied by number of daises he buys should be less than or equal to $40.
framing in equation form we get;
[tex]4r+2d\leq 40[/tex]
Hence The systems of equations are [tex]\left \{ {{r\geq 1; \ \ d+2\leq r} \atop {4r+2d\leq 40}} \right.[/tex] .