A designer is making a rectangular prism box with maximum volume, with the sum of its length, width, and height 8 in. The length must be 2 times the width. What should each dimension be? Round to the nearest tenth of an inch if necessary. A. width: 2 in. length: 4 in. height: 2 in. B. width: 1.8 in. length: 3.6 in. height: 2.6 in. C. width: 3.6 in. length: 1.8 in. height: 2.6 in. D. width: 4 in. length: 2 in. height: 2 in.

Respuesta :

Answer:

B. Width: 1.8 in. Length: 3.6 in. Height: 2.6 in.

Step-by-step explanation:

Let x represent width of the rectangle and y represent height of the prism.

We have been given that the length must be 2 times the width. So length of the prism would be [tex]2x[/tex].

We are also told that the sum of its length, width, and height 8 in. We can represent this information in an equation as:

[tex]x+2x+y=8...(1)[/tex]

[tex]3x+y=8...(1)[/tex]

[tex]y=8-3x...(1)[/tex]

We know that volume of rectangular prism is product of length, width and height.

[tex]V=lwh[/tex]

Upon substituting the values of length, width and height, we will get:

[tex]V=2x\cdot x\cdot y[/tex]

Upon substituting equation (1) in volume formula, we will get:

[tex]V=2x\cdot x\cdot (8-3x)[/tex]

[tex]V=2x^2\cdot (8-3x)[/tex]

[tex]V=16x^2-6x^3[/tex]

Now, we will take the derivative of volume function using power rule as:

[tex]V'=16\cdot 2x^{2-1}-6\cdot 3x^{3-1}[/tex]

[tex]V'=32x-18x^{2}[/tex]

Now, we will equate derivative with zero and solve for x as:

[tex]32x-18x^{2}=0[/tex]

[tex]2x(16-9x)=0[/tex]

[tex]2x=0, (16-9x)=0[/tex]

[tex]x=0, x=\frac{16}{9}[/tex]

[tex]x=0, x\approx 1.8[/tex]

Since width cannot be 0, therefore, the width of prism would be 1.8 inches.

Length of the prism would be [tex]2x\Rightarrow 2(1.8)=3.6[/tex].

Therefore, the length of prism would be 3.6 inches.

Upon substituting [tex]x=1.8[/tex] in equation (1), we will get:

[tex]y=8-3(1.8)[/tex]

[tex]y=8-5.4[/tex]

[tex]y=2.6[/tex]

Therefore, the height of prism would be 2.6 inches and option B is the correct choice.