Answer:
[tex]\frac{1}{2}[sin(x+y)+sin(x-y)][/tex]
Step-by-step explanation:
we know that
To write the products of cosines and sines as sums, we use the following identity, which is called product-to-sum formula:
[tex]cos(A)sin(B)=\frac{1}{2}[sin(A+B)+sin(A-B)][/tex]
In this problem we have
[tex]cos(x)sin(y)[/tex]
therefore
[tex]cos(x)sin(y)=\frac{1}{2}[sin(x+y)+sin(x-y)][/tex]
