The question is incomplete, here is the complete question:
A chemist prepares a solution of sodium thiosulfate by measuring out 110. g of sodium thiosulfate into a 350. mL volumetric flask and filling the flask to the mark with water. Calculate the concentration in mol/L of the chemist's sodium thiosulfate solution. Be sure your answer has the correct number of significant digits.
Answer: The concentration of sodium thiosulfate solution is 1.99 mol/L
Explanation:
To calculate the molarity of solution, we use the equation:
[tex]\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}[/tex]
Given mass of sodium thiosulfate = 110 g
Molar mass of sodium thiosulfate = 158.1 g/mol
Volume of solution = 350 mL
Putting values in above equation, we get:
[tex]\text{Molarity of sodium thiosulfate}=\frac{110\times 1000}{158.1\times 350}\\\\\text{Molarity of sodium thiosulfate}=1.99mol/L[/tex]
Hence, the concentration of sodium thiosulfate solution is 1.99 mol/L
