Answer:
Step-by-step explanation:
Let X represent the units produced day shift while Y night shift.
[tex]H_0: \bar x= \bar y\\H_a: \bar x <\bar y[/tex]
(one tailed test at 1% significance level)
Given are the following data
Group Group One Group Two
Mean 353.00 363.00
SD 25.00 31.00
SEM 3.54 4.18
N 50 55
The mean of Group One minus Group Two equals -10.00
t = 1.8081
df = 103
standard error of difference = 5.531
The one-tailed P value equals 0.03675
Since p >0.01 we accept null hypothesis.
There is no statistical evidence to prove the claim that the number of units produced on the night shift larger