Answer:
7.14 s
Explanation:
The motion of the car is a projectile motion, which consists of two independent motions:
- A uniform motion along the horizontal direction (constant velocity)
- A uniformly accelerated motion along the vertical direction (free fall)
To find the time of flight of the car, we just analyze the vertical motion, using the suvat equation:
[tex]s=ut+\frac{1}{2}gt^2[/tex]
where:
s = 250 m is the vertical displacement, which is equivalent to the height of the cliff (we take the downward direction as positive direction)
u = 0 is the initial vertical velocity of the car
[tex]g=9.8 m/s^2[/tex] is the acceleration due to gravity
t is the time of flight
And solving for t, we find:
[tex]t=\sqrt{\frac{2s}{g}}=\sqrt{\frac{2(250)}{9.8}}=7.14 s[/tex]
