Respuesta :
Answer:
Ionization energy of [tex]He^+[/tex] is 54.4 eV.
Explanation:
[tex]E_n=-13.6\times \frac{Z^2}{n^2}eV[/tex]
where,
[tex]E_n[/tex] = energy of orbit
n = number of orbit
Z = atomic number
Energy of n = 1 in an hydrogen like atom:
[tex]E_1=-13.6\times \frac{2^2}{1^2}eV=-54.4 eV[/tex]
Energy of n = ∞ in an hydrogen like atom:
[tex]E_{\infty }=-13.6\times \frac{2^2}{\infty ^2}eV=0[/tex]
Ionization energy of [tex]He^+[/tex] =
[tex]E=E_{\infty }=E_1=0 - (-54.4 eV)=54.4 eV[/tex]
