Answer:
6.91
Explanation:
For any given height, the terminal velocity Vt = [2W/ρACd]^1/2
where W represent the object's weight, ρ represent the density of the gas, A represent the cross sectional area of the object, and Cd represent the drag coefficient.
v2/v1 = [2W/ρACd]^1/2 / [2W/ρACd]^1/2
v2 and v1 has same weight, influenced by same density of air is 1.2kg/m
and same Cd
v2/v1 = [A2/A1]^1/2
A2 =600 cm2
A1 = πr^2 = π*2^2 = 12.57cm2
v2/v1 = [600/12.57]^1/2 = 6.91
