Answer:
652.6 g of H₃PO₄ are formed
Explanation:
Reaction is:
P₄O₁₀(s) + 6H₂O(l) → 4H₃PO₄(aq)
As P₄O₁₀ is the reactant in excess, the limiting is water.
Ratio is 6:4. We make a rule of three:
6 moles of water produce 4 moles of phosphoric acid
Therefore, 10 moles of water may prodyce (10 .4) / 6 = 6.66 moles of H₃PO₄
We convert the moles to mass:
6.66 moles . 97.9 g / 1mol = 652.6 g
