Note: You may have unintentionally missed to add the diagram, so after a little research I was able to find the diagram, which anyways would help you clear your concept.
Answer:
The function shown in the graph is [tex]y=3(x-2)+1[/tex].
Step-by-step explanation:
From the graph, it is clear that
when x = 0, y = -5
also when x = 2, y = 1
so
[tex]y=3(x-2)+1[/tex]
as
putting (0, -5)
[tex]y=3\left(0-2\right)+1[/tex]
[tex]y=-6+1[/tex]
[tex]y=-5[/tex]
also putting (2, 1)
[tex]y=3(x-2)+1[/tex]
[tex]y=3\left(2-2\right)+1[/tex]
[tex]y=1[/tex]
So, the points (0, -5) and (2, 1) lies on the line [tex]y=3(x-2)+1[/tex].
Also
[tex]y=3(x-2)+1[/tex]
[tex]y=3x-6+1[/tex]
[tex]y=3x-5[/tex]
[tex]\mathrm{For\:a\:line\:equation\:for\:the\:form\:of\:}\mathbf{y=mx+b}\mathrm{,\:the\:slope\:is\:}\mathbf{m}[/tex]
[tex]m=3[/tex]
Therefore, the function shown in the graph is [tex]y=3(x-2)+1[/tex].
Answer:
x^3-2x^2-5x+6
Step-by-step explanation: Edmentum
Used photo math to compare all of the options graphed, and it is definitely x^3-2x^2-5x+6.
Good luck with the final.
