The distance between the two points is [tex]\sqrt{41}[/tex] or 6.4 units
Solution:
The distance between two points is given as:
[tex]d = \sqrt{(y_2-y_1)^2+(x_2-x_1)^2}[/tex]
From figure,
[tex](x_1, y_1) = (-1, 1)\\\\(x_2, y_2) = (4, -3)[/tex]
Therefore,
[tex]d = \sqrt{(-3-1)^2 + (4+1)^2}\\\\d = \sqrt{(-4)^2+(5)^2}\\\\d = \sqrt{16+25}\\\\d = \sqrt{41}\\\\d = 6.403\\\\d \approx 6.4[/tex]
Thus the distance between the two points is [tex]\sqrt{41}[/tex] or 6.4 units
