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A box contains 4 red markers and 2 blue markers a marker is selected at random and it's color is noted. If it is red it is replaced; otherwise it is not. A second marker is selected and it's color is noted. If the second is blue, find the probability that the first was blue?

Respuesta :

Answer:

The probability of first one to be  blue is [tex]\frac{1}{3}[/tex].

Step-by-step explanation:

In the given box, there are 4 red markers and 2 blue markers.

The given scenario will not affect the required probability as the selection of the second one is a case of future.

We need to find the probability of the first marker is blue.

The probability is [tex]\frac{blue markers}{total markers} = \frac{2}{6} = \frac{1}{3}[/tex].

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